The torque required to accelerate the screw The torque required when a heavy object accelerates Calculate the torque required by the motor to drive the load The moment of inertia of a weight converted to the shaft of the motorģ.
Please select the minimum power servo motor to meet the load requirements. Known: load weight MB=200kg, screw pitch PB=20mm, screw diameter DB=50mm, screw weight MB=50kg, friction coefficient μ=0.2, mechanical efficiency η=0.9, load moving speed V=30m/min, the whole moving time T =1.4s, acceleration and deceleration time T1 = T3 =0.2s, static time T4 =0.3s. Calculate the required speed of the motorĪccording to the above data analysis, the minimum motor SM1301520 can be selected. Servo motor rated torque > TF, MAX torque BBB> + TAģ.
The torque required by friction is overcome The principle of installing load inertia 6kg.cm²Ģ. Calculate the load inertia converted to the motor shaft Known: load weight M=50kg, synchronous pulley diameter D=120mm, reduction ratio R1=10,R2=2, friction coefficient between load and machine μ=0.6, load maximum speed 30m/min, load acceleration time from rest to MAX speed 200ms, ignoring the weight of each conveyor pulley, how much power motor is the minimum required to drive such a load?ġ. This transmission mode is the same as the previous transmission mode, and the calculation of load inertia is mainly considered in the selection, and the calculation formula is the same as the previous one.Ĭonclusion: the rotary load mainly considers the calculation of inertia. This transmission mode of resistance is very small, ignoring the torque calculation. Continuous working torque 18803,R BBB>7 output speed =3000/137=22rpm, can not meet the requirements.
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